A positive integer is entered through the keyboard.
Write a function to obtain the prime factors of this number.
For example, prime factors of 24 are 2, 2, 2 and 3, whereas prime factors of 35 are 5 and 7.
#include
main()
{
int number;
int prime(int number);
int primefactor(int number);
printf("Enter the number whose prime factors are to be calculated:");
scanf ("%d", &number);
primefactor(number);
}
//The following function detects a Prime number.
prime(int num)
{
int i, ifprime;
for (i=2; i<=num-1; i++)
{
if (num%i==0)
{
ifprime=0;
}
else
ifprime=1;
}
return (ifprime);
}
//The following function prints the prime factors of a number.
primefactor(int num)
{
int factor,ifprime;
for (factor=2; factor<=num;)
{
prime(factor); //so that the factors are only prime and nothing else.
if (ifprime)
{
if (num%factor==0) //diving by all the prime numbers less than the number itself.
{
printf("%d ", factor);
num=num/factor;
continue;
}
else
{
factor++;//this cannot be made a part of the for loop
}
}
}
return 0;
}
Calculation of A to the power of B using Functions
Write a function power(a,b), to calculate the value of a raised to b.
#include
main()
{
int power (a,b);
int a, b, result;
printf("Enter the value of a and b:");
scanf ("%d %d", &a, &b);
result=power(a,b);
printf("%d raised to %d is %d", a, b, result);
}
power (int a, int b)
{
int calculation=1, calc;
for (calc=1; calc <=b; calc++)
{
calculation=calculation*a;
continue;
}
return(calculation);
}
Conver the given year to Roman Numerals using Functions.
Write a general-purpose function to convert any given year into its roman equivalent.
The following table shows the roman equivalents of decimal numbers:
Decimal:........Roman
1.....................i
5....................v
10..................x
50..................l
100................c
500...............d
1000.............m
Example:
Roman equivalent of 1988 is mdcccclxxxviii
Roman equivalent of 1525 is mdxxv
This program is a big lengthy owing to the use of Case Statements. This program can also be rewritten using Arrays, which will reduce the length considerably.
#include
main()
{
int year;
int convert (int year);
{
printf("Note:Enter a four year digit year.\n\n");
printf("Enter the year that you wanna convert to Roman: " );
scanf ("%d", &year);
if (year> 1999)
{
printf("Invalid Year.Please enter again.\n\n");
}
}
convert(year);
}
convert(int year)
{
int i;
printf("\nYear converted to Roman:");
i=(year/1000); //thousands place
if(i==1)
{
printf("m");
}
i=((year/100)%10); //hundreds place
switch (i)
{
case 1:
printf("c");
break;
case 2:
printf("cc");
break;
case 3:
printf("ccc");
break;
case 4:
printf("cd");
break;
case 5:
printf("d");
break;
case 6:
printf("dc");
break;
case 7:
printf("dcc");
break;
case 8:
printf("dccc");
break;
case 9:
printf("dcccc"); //this part you may think is wrong..9 -> cm
break; //but i have taken a hint from the example in the question.
}
i=((year/10)%10); //tens place
switch(i)
{
case 1:
printf("x");
break;
case 2:
printf("xx");
break;
case 3:
printf("xxx");
break;
case 4:
printf("xl");
break;
case 5:
printf("l");
break;
case 6:
printf("lx");
break;
case 7:
printf("lxx");
break;
case 8:
printf("lxxx");
break;
case 9:
printf("lxxxx"); //had it not been for this example, it would have been xc
break;
}
i=year%10; //ones place
switch(i)
{
case 1:
printf("i");
break;
case 2:
printf("ii");
break;
case 3:
printf("iii");
break;
case 4:
printf("iv");
break;
case 5:
printf("v");
break;
case 6:
printf("vi");
break;
case 7:
printf("vii");
break;
case 8:
printf("viii");
break;
case 9:
printf("ix");
break;
}
printf ("\n\n");
return 0;
}
Detection of Leap year using Functions.
Any year is entered through the keyboard.
Write a function to determine whether the year is a leap year or not.
#include
main()
{
int leap_year(year);
int year, lp;
printf("Enter the year:");
scanf ("%d", &year);
lp=leap_year(year);
if (lp)
{
printf("\nThe entered year is a leap year.");
}
else
{
printf("\nThe entered year is not a leap year.");
}
}
leap_year(int y)
{
int lp;
if (y%4==0)
{
lp=1;
}
else
lp=0;
return(lp);
}
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